Say you have an array for which the ith element is the price of a given stock on day i.

If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit.

Example 1:

Input: [7, 1, 5, 3, 6, 4]Output: 5max. difference = 6-1 = 5 (not 7-1 = 6, as selling price needs to be larger than buying price)

 

Example 2:

Input: [7, 6, 4, 3, 1]Output: 0In this case, no transaction is done, i.e. max profit = 0. 遍历一边，找到low值or去减low值

class Solution(object):    def maxProfit(self, prices):        """        :type prices: List[int]        :rtype: int        """        max_profit = 0        n=len(prices)        if n<1:            return max_profit        low=prices[0]        for index in range(n):            if prices[index]